AmericanLongRifles Forums

General discussion => Contemporary Accoutrements => Topic started by: LRB on February 12, 2011, 02:11:50 AM

Title: PC/HC English Scalper
Post by: LRB on February 12, 2011, 02:11:50 AM
Just finished this one. A PC version of the classic English scalper knife. 7 1/8" blade of 01 steel, tapered in both directions. Blade and tang. A Boxwood handle secured with iron rivet pins. The handle is oversized as were the originals, having a slight overlapped gap on the under side, and extending into the blade area a tad bit. This is the typical English trade scalper of the 18th c., but with a superior steel, and an epoxy sealed tang to prevent water intrusion. The sheath is a center seam up the backside, of 6/7 oz vege-tan tooling leather, stained black with the vinegar/iron natural stain. I am beginning to love this stuff. It does not rub off onto your clothing. Hope you enjoy a look. I am well pleased as to how it all came out. I plan to do the French type also, when I get some time. Thankyou for any comments, or critiques.

(https://americanlongrifles.org/forum/proxy.php?request=http%3A%2F%2Fi37.photobucket.com%2Falbums%2Fe77%2Fwicklrb%2FPicture078.jpg&hash=2716058cdb85af77e0032205f654b27da54572bf)
Title: Re: PC/HC English Scalper
Post by: Tim Crosby on February 12, 2011, 02:23:02 AM
   Really nice work, as always Wick. The handle looks familiar, English Boxwood grows so slow a piece like that has got to be not only old by hard to find. 

 Tim C.
Title: Re: PC/HC English Scalper
Post by: wattlebuster on February 12, 2011, 05:01:42 PM
I like it
Title: Re: PC/HC English Scalper
Post by: KennyC on March 06, 2011, 06:31:40 AM
That is some sweet !!!
Title: Re: PC/HC English Scalper
Post by: David G on March 07, 2011, 03:56:23 AM
Wow Wick! As much as I like the knife I like that sheath equally as well. You nailed 'em both. Great work.
Title: Re: PC/HC English Scalper
Post by: Paddlefoot on March 07, 2011, 04:35:46 AM
Very nice piece of work sir. How many coats of stain on the sheath to get it that dark?